Home > Error Cannot > Error Cannot Find The Byte Order For This Architecture

Error Cannot Find The Byte Order For This Architecture

But the multi-character constant is indeed completely legal as-is. –Damon Feb 10 at 15:05 add a comment| up vote 1 down vote I once used a construct like this one: uint16_t share|improve this answer edited Sep 22 '12 at 9:31 CharlesB 42.2k11117136 answered Nov 21 '10 at 20:03 Daniel Băluţă 1,020811 Why is this not reliable? Install Setup not working A power source that would last a REALLY long time What news about the second Higgs mode (or the mysterious particle) is anticipated to be seen at LITTLE \ : *(const char *)&endianness == 0xde ? http://oncarecrm.com/error-cannot/error-cannot-find.html

If you stick to standard C, declarating a variable in memory requires a statement, but returning a value requires an expression. Identifying a Star Trek TNG episode by text passage occuring in Carbon Based Lifeforms song "Neurotransmitter" Why are so many metros underground? Last modified: Mon Oct 10 15:09:35 2016; Machine Name: buxtehude Debian Bug tracking system Copyright (C) 1999 Darren O. Skip to content Ignore Learn more Please note that GitHub no longer supports old versions of Firefox. http://antmeetspenguin.blogspot.com/2012/08/hping3-error-dbyteorderbiglittleendian.html

If that byte is 1, then the system is little endian, otherwise it's big endian. How to escape Linux commands for the WordPress editor Internet Explorer can't access https page - maybe a client CERT is needed? Feb 25 at 13:54 | show 8 more comments up vote 6 down vote Not during compile time, but perhaps during runtime. is missing|error in pkg_delete|filesystem was touched prior to .make install|list of extra files and directories|list of files present before this port was installed|list of filesystem changes from before and after|Error: Files

I only tested this on a little endian machine under msvc. share|improve this answer edited Feb 24 at 10:11 answered Jun 26 '14 at 13:01 towi 7,409854125 1 +1. big endian0How can I convert little endian to big endian using htonl2Add two big endian values on little endian machine3Endianness macro in C0C little endian but produce big endian result?1Confusion in e|error: passing.*(a.*value|incompatible type)|error: qualified reference|error: redeclaration of.*built-in type|error:.*requires a (constant expression|pointer or reference|type specifier)|error: redefinition of|error: switch condition has boolean|error: taking the address of a temporary object|error: target.*conflicts with declaration|error:.*unable to

Namely htons(), htonl(), ntohs() and ntohl() ...where n is "network" (ie. For instance using a union, typedef union { uint32_t word; uint8_t bytes[4]; } byte_check; or casting, uint32_t word; uint8_t * bytes = &word; Please note that for completely portable endianness checks, Why aren't Muggles extinct? https://github.com/rethinkdb/rethinkdb/issues/5809 Terms Privacy Security Status Help You can't perform that action at this time.

Should be safe to use. Join them; it only takes a minute: Sign up Determining endianness at compile time up vote 35 down vote favorite 11 Is there a safe, portable way to determine (during compile more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed so it's not guaranteed to work. –Alex Jun 23 '14 at 0:46 | show 2 more comments up vote 18 down vote With C99, you can perform the check as: #define

I'm not sure if it is possible to check at compile time for it. –Tyzoid Mar 10 at 21:53 So, do you feel the snippet you provided is general How can I have low-level 5e necromancer NPCs controlling many, many undead in this converted adventure? It is implementation-defined behavior C11 10. How can I list two concurrent careers, one full time and one freelance, on a CV?

You can't know. http://oncarecrm.com/error-cannot/error-cannot-find-helpctr.html I actually do understand why this works myself, but the syntax might be a bit cryptic for some. –einpoklum Jun 28 at 0:40 using boost in C++: #include Generally, you do storage - to disk, or network - using 'network endian', which is BIG endian, and local computation using host endian (which on x86 is LITTLE endian). Lyadvinsky Nov 21 '10 at 20:13 See my answer which should do it at compile-time, as long as you don't mind requiring (at least partial) C99 support in the

i have installed all the dependencies mentioned and also "npm". edit for runtime checking bool isLittleEndian() { short int number = 0x1; char *numPtr = (char*)&number; return (numPtr[0] == 1); } Create an integer, and read its first byte (least significant FC2Ad かるかん 備忘録的にゃ。 BSD linuxに関連することも書いてますが、書いてある内容を保障しません。             広告はすべてアフィリエイトです。小銭稼ぎ。売れる気配なし・・・ プロフィール Author:こびゃ ↑うちのネコ、ムー16歳。ちょっと太目の9.0Kg生まれてすぐ捨てられた。が管理人のこびゃに拾われすくすくと育つ。いまではこびゃ家の主。しっぽを触るとキレル。シャンプー後の髪のにおいをこよなく愛   RSSリンクの表示 最近記事のRSS 最新コメントのRSS 最新トラックバックのRSS 最近の記事 Linux システム時間の表示とか (07/06) navigate here I edited it so that it has: #define BYTE_ORDER_LITTLE_ENDIAN /* # error can not find the byte order for this architecture, fix bytesex.h */ Now I can run make.

I've also faced this same situation on SLES - can't find a package for hping anywhere - and found the same recipe below works to compile hping3. The result is of course implementation defined, but that's what it has to be since the order of bytes (which is just what you're trying to figure out!) is implementation-defined. Fortunately, they have documented their predefined macros here, and you can use the target processor architecture to infer the endianness.

I am using the following code but converting it to macro would be too long.

share|improve this answer edited Nov 22 '10 at 0:04 Matt Joiner 41.5k44214382 answered Nov 21 '10 at 20:46 R.. 127k15187421 6 No, it isn't, not even when you give it Browse other questions tagged c++ c architecture macros endianness or ask your own question. See http://unixpapa.com/incnote/byteorder.html - DrJ */ #include main() { printf("Hello World"); int ans = am_big_endian(); printf("am_big_endian value: %d",ans); } int am_big_endian() { long one= 1; return !(*((char *)(&one))); } You use htons() and ntohs() and friends to convert between the two.

Can Tex make a footnote to the footnote of a footnote? The following fails to compile because. /** isLittleEndian::result --> 0 or 1 */ struct isLittleEndian { enum isLittleEndianResult { result = (O32_HOST_ORDER == O32_LITTLE_ENDIAN) }; }; –user48956 Aug 13 '10 at Something like if( (char[4])(U'A')[0] == 65) would do, if the cast was legal. his comment is here make[2]: Leaving directory '/root/amit/rethinkDB/rethinkdb/build/external/v8_3.30.33.16/build' Full error log: ./build/external/v8_3.30.33.16_install.log mk/support/build.mk:121: recipe for target 'build/external/v8_3.30.33.16/lib/libv8.a' failed make[1]: *** [build/external/v8_3.30.33.16/lib/libv8.a] Error 1 Makefile:52: recipe for target 'make' failed make: *** [make] Error 2 [email protected]:~/amit/rethinkDB/rethinkdb#

Copy sent to Vincent Tantardini . On Solaris/SPARC the same compiler gcc 4.3.3 gives the right answer, but SUNStudio 12 compiler will have the same behaviour as the gcc 4.3.4 on x86 used at that link. undeclared|error: .struct utmpx. must return .int.|invalid conversion from|cannot be used as a macro name as it is an operator in C\+\+|is not a member of type|after previous specification in|no class template named|because worst conversion

Inspired I wrote this C program to find out and remove all doubt: /* returns true if system is big_endian. Is my teaching attitude wrong? Syntax Design - Why use parentheses when no arguments are passed? switch('AB') { case 0x4142: printf("ASCII Big endian\n"); break; case 0x4241: printf("ASCII Little endian\n"); break; case 0xC1C2: printf("EBCDIC Big endian\n"); break; case 0xC2C1: printf("EBCDIC Little endian\n"); break; } EDIT: Found even a

It's as compile time as it gets. Debian bug tracking system administrator .